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Question

Sound wave of frequency 600 Hz fall normally on a perfect reflecting wall. The minimum distance from the wall at which particles of the medium will have maximum displacement during its vibrations is 
[speed of sound =300 m/s]
  1. 78 m
  2. 38 m
  3. 18 m
  4. 58 m


Solution

The correct option is C 18 m
Displacement of particles of the medium near wall will be zero, hence minimum distance d from wall of particles of the medium having maximum displacement during its vibrations will be λ4.  
So, d=λ4


We know that velocity of sound wave is given by,
v=λf, where λ is wavelength and f is frequency.
λ=vf
λ=300600=12 m
Now,
d=λ4=12×4=18 m
 

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