Question

Sound waves of frequency $320Hz$ are sent into the top of a vertical tube containing water at a level that can be adjusted. Standing waves are produced at two successive water levels $44cm$ and $74cm$ from open end. The distance (in $cm$) of nearest displacement antinode from open end is

Answer 1

Step 1: Draw a block diagram for the given question.

Step 2: Find the distance of nearest displacement antinode from end.

Frequency of sound wave is $320Hz$.

Standing waves are produced at two successive water levels from open end,

$l_1=44cm\text{a}nd{l}_2=74cm$.

The distance (in $cm$) of nearest displacement antinode from open end is,

$e=\frac{3l_2-5l_1}{2}$

$e=\frac{(3\times 74)-(5\times 44)}{2}$

$e=\frac{222-220}{2}$

$e=1cm$

Final Answer: $1$