Sourabh deposited certain sum of money for 1 year at rate of 6% p.a. If he got the maturity amount as Rs 7434, The amount he deposited every month in his recurring deposit account is
Rs.600
Given n = 1year = 12 month
r = 6% p.a.
Let Principal be p
Amount deposited = n ×p= P ×12
Interest = p×n(n+1)2×12(r100)
I = p×12×132×12(6100)
Maturity amount = Amount deposited + Interest
Maturity amount = 12 P + 39P100
7434 = 39P1001200P+39P1001239P=743400
P= Rs. 600