Question

A bullet of mass 20 g moving with a speed of 500 m/s strikes a wooden block of mass 1 kg and gets embedded in it. Find the speed with which block moves along with the bullet.

Answer 1

Dear Student
m₁ = 20g = 0.020kg

u₁ = 500m/s

m₂ = 1kg

u₂ = 0

For final mass = (m₁ + m₂) =(1+0.020 ) =1.020 kg
v_final = ?

m₁u₁ + m₂ u₂ = mv


0.02 × 500 + 0 = (1 + 0.02) v

10 = 1.02v

10 / 1.02 = v

v = 9.80m/s

Regards