If three resistance 10 -8486-20 -8486-30 -8486- connected in parallel with 2-5 V battery nbsp-then calculate total current supply in circuit

Dear #160;Student,Given,R1=10 #937;, #160;R2=20 #937;, #160;R3=30 #937;, #160;V=2.5VFor #160;parallel #160;connection, #160;total #160;res ...

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Standard XII

Physics

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If three resi...

Question

If three resistance 10 Ω,20 Ω,30 Ω, connected in parallel with 2.5 V battery then calculate total current supply in circuit

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Solution

$D e a r S t u d e n t, G i v e n, R_{1} = 10 Ω, R_{2} = 20 Ω, R_{3} = 30 Ω, V = 2.5 V F o r p a r a l l e l c o n n e c t i o n, t o t a l r e s i s \tan c e i s, \frac{1}{R_{p}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} = \frac{1}{10} + \frac{1}{20} + \frac{1}{30} = \frac{6 + 3 + 2}{60} = \frac{11}{60} Ω \Rightarrow R_{p} = \frac{60}{11} Ω M a i n c u r r e n t i n t h e c i r c u i t i s, I = \frac{V}{R_{p}} = \frac{2.5}{\frac{60}{11}} = \frac{27.5}{60} = 0.458 A R e g a r d s .$

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If three resistance 10 Ω,20 Ω,30 Ω, connected in parallel with 2.5 V battery then calculate total current supply in circuit

Dear Student,Given,R1=10Ω, R2=20Ω, R3=30Ω, V=2.5VFor parallel connection, total resistance is,1Rp=1R1+1R2+1R3=110+120+130=6+3+260=1160Ω⇒Rp=6011ΩMain current in the circuit is,I=VRp=2.56011=27.560=0.458ARegards.