Solve this-6- A body of mass 1 kg is thrown upwards with a nbsp-velocity 20 m-s- It momentarily comes to rest after nbsp-attaining a height of 18 m- How much energy is nbsp-lost due to air friction - -g - 10 m-s2- -1- 10 J nbsp- nbsp- nbsp- nbsp- nbsp-2- 20 J nbsp-3- 30 J nbsp- nbsp- nbsp- nbsp- nbsp-4- 40 J- nbsp-

Dear #160;Student #160;, #160;When #160;the #160;body #160;is #160;thrown #160;upwards. #160;its #160;K.E #160;is #160;converted #160; ...

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Standard IX

Physics

Acceleration Due to Gravity

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Question

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6. A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction ? (g = 10 m/s²) :-

(1) 10 J (2) 20 J
(3) 30 J (4) 40 J

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Solution

$D e a r S t u d e n t, W h e n t h e b o d y i s t h r o w n u p w a r d s . i t s K . E i s c o n v e r t e d i n t o P . E . T h e l o s s o f e n e r g y d u e t o a i r f r i c t i o n i s t h e d i f f e r e n c e o f K . E a n d P . E \frac{1}{2} m v ² - m g h = \frac{1}{2} x 1 x 400 - 1 x 18 x 10 = 200 - 180 = 20 J R e g a r d s$

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Solve this: 6. A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction ? (g = 10 m/s2) :- (1) 10 J (2) 20 J (3) 30 J (4) 40 J

Dear Student , When the body is thrown upwards. its K.E is converted into P.E. The loss of energy due to air friction is the difference of K.E and P.E 12 mv² – mgh =12 x 1 x 400 – 1 x 18 x 10 = 200 – 180 = 20 JRegards

Solve this:

6. A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction ? (g = 10 m/s²) :-

(1) 10 J (2) 20 J
(3) 30 J (4) 40 J