Help in this question-Problem-10 What is the purity of conc- H2SO4 solution -specific gravity 1-8 g-mL- if 5-0 mL of this nbsp-solution is neutralized by 84-6 mL of 2-0 N NaOH - nbsp- nbsp-

Dear Student, Specific #160;gravity #160;= #160;mass #160;volumemass #160;= #160;5ml #160;x #160;1.8g/ml #160;= #160;9gMolarity #160;= # ...

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Standard XII

Chemistry

Laws of Definite Proportions, Multiple Proportions

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Problem.10 What is the purity of conc. H₂SO₄ solution (specific gravity 1.8 g/mL), if 5.0 mL of this solution is neutralized by 84.6 mL of 2.0 N NaOH ?

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Solution

Dear Student,
$S p e c i f i c g r a v i t y = \frac{m a s s}{v o l u m e} m a s s = 5 m l x 1.8 g / m l = 9 g M o l a r i t y = \frac{m o l e s o f s o l u t e}{v o l u m e o f} N_{1} V_{1} = N_{2} V_{2} N_{1} x 5 = 84.6 x 2 N_{1} = 33.84 N N o r m a l i t y = \frac{w e i g h t i n g m x 1000}{e q u i v a l e n t w e i g h t} w e i g h t i n g m = \frac{33.84 x 1000}{98} = 3.31 g t h u s p u r i t y i s 3.31 %$

Regards,

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Help in this question: Problem.10 What is the purity of conc. H2SO4 solution (specific gravity 1.8 g/mL), if 5.0 mL of this solution is neutralized by 84.6 mL of 2.0 N NaOH ? ​

Dear Student, Specific gravity = mass volumemass = 5ml x 1.8g/ml = 9gMolarity = moles of solutevolume of N1V1=N2V2N1x5 = 84.6x2N1=33.84NNormality=weight in gm x 1000equivalent weightweight in gm = 33.84 x 100098=3.31gthus purity is 3.31% Regards,

Help in this question:

Problem.10 What is the purity of conc. H₂SO₄ solution (specific gravity 1.8 g/mL), if 5.0 mL of this solution is neutralized by 84.6 mL of 2.0 N NaOH ?