Question

question no. 6

Q6. If 3$\mathrm{\theta }$ is an acute angle, solve the following equation for ​​$\mathrm{\theta }$ :

(cosec 3​$\mathrm{\theta }$ – 2) (cot 2​$\mathrm{\theta }$ – 1) = 0.

Answer 1

Dear Student,

$$\begin{gathered} \left(\cos ec3\theta -2\right)\left(cot2\theta -1\right)=0 \\ \Rightarrow either\cos ec3\theta -2=0ORcot2\theta -1=0 \\ \Rightarrow either\cos ec3\theta =2ORcot2\theta =1 \\ \Rightarrow 3\theta =\frac{\mathrm{\pi }}{6}OR2\theta =\frac{\mathrm{\pi }}{4} \\ \Rightarrow \theta =\frac{\mathrm{\pi }}{18}OR\theta =\frac{\mathrm{\pi }}{8} \end{gathered}$$

Regards