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B-3 solve

QB-3. Find the moment of inertia of a uniform half-disc about an axis perpendicular to the plane and passing through its centre of mass. Mass of this disc is M and radius is R.

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Solution


Dear Student,
Here mass of the half disk is M then mass per unit area (σ) =2MπR2So let a strip at radius r of dr thickness so area of this strip =πrdrnow moment of inertia of this strip=dI=πrdr σr2so total inertia of the half disk=0Rπrdr σr2=0R2MR2r3dr=MR22
Regard

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