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Q5. The average atomic mass of a sample of an element X is 16.2 u. What are the percentages of isotopes 8 X¹⁶ and 8 X¹⁸ in the sample ?

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Solution

$l e t t h e p e r c e n t a g e o f b e q % t h e n 16.2 = 16 q + 18 (100 - q) 0.2 q = 1800 - 18 q 18.2 q = 1800 q = \frac{1800}{18.2} = 98.9 p e r c e n t a v a i l a b i l i t y o f 16 1.1 % o f 18 R e g a r d s$

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