13x + 15y = 189
Therefore 15y = 189 – 13x
When y is largest, x must have the least possible value.
15y is divisible by 15. Hence R.H.S. of the equation also should be divisible by 15.
The least value of x for which R.H.S. is divisible by 15 is x = 3
When x = 3; 15y = 189 – 13(3) = 189 – 39 = 150
i.e. 15y = 150; or y = 10
Hence, the required solution is x = 3; y = 10