Question-8-Q8- A chain of mass M is placed on a smooth table with 1-n of its length L hanging over the edge- The work done in pulling the hanging portion of the chain back to the surface of the table is-A- MgL-n nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- -B- MgL-2n nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- -C- MgL-n2 nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- -D- MgL-2n2- nbsp-

Dear Student, the #160;work #160;done #160;is #160;equal #160;to #160;gain #160;potential #160;energy #160;of #160;the #160;spring #16 ...

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Byju's Answer

Standard XII

Physics

Work by Multiple Forces

Question.8. ...

Question

Question.8.

Q8. A chain of mass M is placed on a smooth table with 1/n of its length L hanging over the edge. The work done in pulling the hanging portion of the chain back to the surface of the table is-

(A) MgL/n (B) MgL/2n (C) MgL/n² (D) MgL/2n²

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Solution

Dear Student,

$t h e w o r k d o n e i s e q u a l t o g a i n p o t e n t i a l e n e r g y o f t h e s p r i n g p a r t t h a t i s h a n g i n g . w e d o t h i s q u e s t i o n w i t h c e n t e r o f m a s s . t h e m a s s o f t h e h a n g i n g p a r t m = \frac{M}{n} c e n t e r o f m a s s o f t h e h a n g i n g p a r t i s a t d e p t h o f \frac{L}{2 n} w o r k d o n e = m g (\frac{L}{2 n}) = (\frac{M}{n}) g (\frac{L}{2 n}) = \frac{M g L}{2 n^{2}} o p t i o n D R e g a r d s$

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Question.8. Q8. A chain of mass M is placed on a smooth table with 1/n of its length L hanging over the edge. The work done in pulling the hanging portion of the chain back to the surface of the table is- (A) MgL/n (B) MgL/2n (C) MgL/n2 (D) MgL/2n2

Dear Student, the work done is equal to gain potential energy of the spring part that is hanging .we do this question with center of mass .the mass of the hanging part m=Mncenter of mass of the hanging part is at depth of L2nwork done =mgL2n=MngL2n=MgL2n2option DRegards

Question.8.

Q8. A chain of mass M is placed on a smooth table with 1/n of its length L hanging over the edge. The work done in pulling the hanging portion of the chain back to the surface of the table is-

(A) MgL/n (B) MgL/2n (C) MgL/n² (D) MgL/2n²