Solve this-Q- A container can hold nbsp-4847litres of milk- How much milk is contained in the container when it is nbsp-35th full-

Capacity #160;of #160;container #160;= #160;4847 #160;litres #160;= #160;3407 #160;litresQuantity #160;of #160;milk #160;in #160;the # ...

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Standard X

Mathematics

Euclid's Division Algorithm

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Q. A container can hold $48 \frac{4}{7}$ litres of milk. How much milk is contained in the container when it is $\frac{3}{5}$ th full?

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Solution

$Capacity of container = 48 \frac{4}{7} litres = \frac{340}{7} litres Quantity of milk in the container = \frac{3}{5} of \frac{340}{7} litres = \frac{3}{5} \times \frac{340}{7} = \frac{204}{7} litres = 29 \frac{1}{7} litres$

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Solve this. Q. A container can hold 4847litres of milk. How much milk is contained in the container when it is 35th full?

Capacity of container = 4847 litres = 3407 litresQuantity of milk in the container = 35 of 3407 litres=35×3407=2047 litres=2917 litres

Solve this.
Q. A container can hold $48 \frac{4}{7}$ litres of milk. How much milk is contained in the container when it is $\frac{3}{5}$ th full?

$Capacity of container = 48 \frac{4}{7} litres = \frac{340}{7} litres Quantity of milk in the container = \frac{3}{5} of \frac{340}{7} litres = \frac{3}{5} \times \frac{340}{7} = \frac{204}{7} litres = 29 \frac{1}{7} litres$