Question

Find the value of x:


$$\begin{gathered} \mathrm{Solve}: \\ \frac{\left(\mathrm{x}-0.4\right)0.5}{0.35}-\left(\mathrm{x}+6.1\right)=\frac{\left(\mathrm{x}-2.71\right)0.6}{0.42} \end{gathered}$$

Answer 1

Dear student,

$$\begin{gathered} Wehave, \\ \frac{\left(x-0.4\right)0.5}{0.35}-\left(x+6.1\right)=\frac{\left(x-2.71\right)0.6}{0.42} \\ \Rightarrow \frac{\left(x-0.4\right)}{0.7}-\left(x+6.1\right)=\frac{\left(x-2.71\right)}{0.7} \\ \Rightarrow \frac{x-0.4-0.7x-4.27}{\sout{0.7}}=\frac{\left(x-2.71\right)}{\sout{0.7}} \\ \Rightarrow 0.3x-4.67=x-2.71 \\ \Rightarrow 0.3x-x=-2.71+4.67 \\ \Rightarrow -0.7x=1.96 \\ \Rightarrow x=\frac{1.96}{-0.7} \\ \Rightarrow \boxed{x=-2.8} \end{gathered}$$

Regards