Tell experts

Q. If in second equation of motion if s stands for distance
Distance = vector quantity
U = initial velocity
Velocity = scaler quantity
It says that scaler = vector
How ?

Open in App

Solution

Dear student,
$S = u t + \frac{1}{2} a t^{2} u t = v e l o c i t y \times t i m e = d i s \tan c e a t^{2} = a c c e l e r a t i o n \times t i m e \times t i m e = d i s \tan c e s o s e c o n d e q u a t i o n o f m o t i o n i s v e r f i e d a s L H S = R H S R e g a r d s$

Suggest Corrections

Similar questions

Q. Difference between vector quantity and Scaler quantity?

Q. Explain the scaler and vector quantity

Q. What are the physical quantities on which vectors and scalers are differentiated?

The vector quantity is :

(a) work (b) pressure

Displacement does not have direction as it is the shortest distance between initial and starting point; then why is displacement a vector quantity and distance a scalar quantity?

Join BYJU'S Learning Program

Tell experts Q. If in second equation of motion if s stands for distance Distance = vector quantity U = initial velocity Velocity = scaler quantity It says that scaler = vector How ?

Dear student, S=ut+12at2ut=velocity ×time=distanceat2=acceleration×time ×time=distanceso second equation of motion is verfied as LHS=RHSRegards

Tell experts

Q. If in second equation of motion if s stands for distance
Distance = vector quantity
U = initial velocity
Velocity = scaler quantity
It says that scaler = vector
How ?

Dear student,
$S = u t + \frac{1}{2} a t^{2} u t = v e l o c i t y \times t i m e = d i s \tan c e a t^{2} = a c c e l e r a t i o n \times t i m e \times t i m e = d i s \tan c e s o s e c o n d e q u a t i o n o f m o t i o n i s v e r f i e d a s L H S = R H S R e g a r d s$