Special product and expansion
If $a + b + c = 11$ and $a b + b c + c a = 36$ , find the value of $a^{2} + b^{2} + c^{2}$

Open in App

Solution

We know that:
$(a + b + c)^{2} = a^{2} + b^{2} + c^{2} + 2 (a b + b c + c a)$
$(11)^{2} = a^{2} + b^{2} + c^{2} + 2 (36)$
$a^{2} + b^{2} + c^{2} = 121 - 72$
$a^{2} + b^{2} + c^{2} = 49$ .

Suggest Corrections

Similar questions

a + b + c = 6

a b + b c + c a = 11

a^{2} + b^{2} + c^{2}

If $a b + b c + c a = 36$ and $a^{2} + b^{2} + c^{2} = 85$ then find $a + b + c$ .

If a + b + c = 11 and $a^{2} + b^{2} + c^{2} = 81$ , find ; $a b + b c + c a$ .

If $a + b + c = 10$ and $a^{2} + b^{2} + c^{2} = 36$ , then $a b + b c + c a =$ .......... .

\frac{a^{2} + b^{2} + a b}{b^{2} + c^{2} + b c} + \frac{c^{2} + c a + a^{2}}{b^{2} + c^{2} + b c}

Join BYJU'S Learning Program