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Question

Special product and expansion 
If $$a+b+c=11$$ and $$ab+bc+ca=36$$, find the value of $$a^{2}+b^{2}+c^{2}$$


Solution

We know that:
$$(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)$$
$$(11)^2=a^2+b^2+c^2+2(36)$$
$$a^2+b^2+c^2=121-72$$
$$a^2+b^2+c^2=49$$.

1244172_1300622_ans_61444a658c524dd19c8a3f294d8bf89f.jpg

Mathematics

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