Species acting as Bronsted acid and base is:

H {S O}_{4}^{-}

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{N a}_{2} {C O}_{3}

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{N H}_{3}

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{O H}^{-}

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Solution

The correct option is A $H {S O}_{4}^{-}$
$H {S O}_{4}^{-}$ can accept proton to form $H_{2} S O_{4}$ and also give a proton to form ${S O}_{4}^{2 -}$ therefore, it acts both as Bronsted acid as well as base.

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H_{2} O, {H C O}_{3}^{-}, {H S O}_{4}^{-}

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{N H}_{3}, {H S O}_{4}^{-}, H_{2} {S O}_{4}, {H C O}_{3}^{-}, H_{3} O

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