Species formed in experiment A does not give test of Cu2+. It is due to the formation of:
A
[Cu(NH3)4]Cl
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B
[Cu(NH3)4]SO4
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C
Cu(OH)2
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D
Cu
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Solution
The correct option is B[Cu(NH3)4]SO4
Option (B) is correct. Species formed in experiment A does not give test of Cu2+. It is due to the formation of [Cu(NH3)4]SO4.
When FeSO4 and (NH4)2SO4 solution are mixed, a double salt is formed. It has the formula FeSO4(NH4)2SO4.6H2O. In aqueous solution, the salt dissociates.
When CuSO4 and NH3 are mixed in the molar ratio of 1:4 in solution, a complex [Cu(NH3)4]SO4 is formed. It is a coordinated compound and dissociates to form [Cu(NH3)4]2+ and SO2−4.