Specific conductance of a decinormal solution of KCl is 0.0112ohm−1cm−1. The resistance of a cell containing the solution was found to be 56. Waht is the cell constant?
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Solution
We know that, Sp.conductance=Cellconstant×Conductance or Cellconstant=Sp.conductanceConductance =Sp.conductance×Resistance =0.0112×56 =0.6272cm−1.