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Electrochemical Cells, Galvanic Cells

Specific cond...

Question

Specific conductivity of $0.20 M$ solution of $K C l$ at $298 K$ is $0.025$ $S$ ${c m}^{- 1}$ . Calculate its molar conductivity.

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Solution

The molar conductivity $Λ_{m} = \frac{1000 κ}{C}$
$Λ_{m} = \frac{1000 c m^{3} / d m^{3} 0.025 S / c m}{0.20 m o l d m^{- 3}}$
$Λ_{m} = 125 S m o l^{- 1} c m^{2}$
The molar conductivity is $125 S m o l^{- 1} c m^{2}$

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