MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Electrochemical Cells, Galvanic Cells

Specific cond...

Question

Specific conductivity of $0.20 M$ solution of $K C l$ at $298 K$ is $0.025$ $S$ ${c m}^{- 1}$ . Calculate its molar conductivity.

Open in App

Solution

The molar conductivity $Λ_{m} = \frac{1000 κ}{C}$
$Λ_{m} = \frac{1000 c m^{3} / d m^{3} 0.025 S / c m}{0.20 m o l d m^{- 3}}$
$Λ_{m} = 125 S m o l^{- 1} c m^{2}$
The molar conductivity is $125 S m o l^{- 1} c m^{2}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The conductivity of 0.20 M solution of

K C l

0.0248 S c m^{- 1}

. Calculate its molar conductivity.

Q. Electrolytic conductivity of 0.02 mol/l solution of kcl at 298k is 2.48x10^-2 ohm^-1 cm^-1. Calculate it's molar conductivity.

Q. Molar conductivity of

0.15

M solution of KCl at

298

K, if its conductivity is

0.0152

c m^{- 1}

Q. The conductivity of 0.2 M KCl solution is

3 \times 10^{- 2} o h m^{- 1} c m^{- 1}

. Calculate its molar conductance.

Q. Electrolytic conductivity of

0.3 M

K C I

298 K

3.72

10^{- 2} S c m^{- 1}

.Calculate its molar conductivity (

S c m^{2} m o l^{- 1}

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Electrochemical Cell

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Electrochemical Cells, Galvanic Cells

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon