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Question

Specific heat and equivalent wt. of a metal are =0.057calg1 and 38.24 respectively. It's exact atomic weight is?

A
114.72g
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B
38.297g
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C
110.9g
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D
uncertain
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Solution

The correct option is C 114.72g
Solution:- (A) 114.72g.
Given that specific heat of metal =0.057calg1
According to Dulong Petit law,
Approximate atomic weight=6.4specific heat=6.40.057=112.28g
Equivalent weight of metal =38.24g(Given)
Now applying-
valency=Approximate atomic weightEquivalent weight=112.2838.24=2.933
Exact atomic weight=valency×Equivalent weight
Exact atomic weight=3×38.24=114.72g
Hence the exact atomic weight of metal is 114.72g.

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