Specific heat capacity of lead is $120 J k g^{- 1} K^{- 1}$ . When $7200 J$ of heat is supplied to $5 k g$ of lead, the rise in temperature is

8^{\circ} C

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10^{\circ} C

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12^{\circ} C

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14^{\circ} C

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Solution

The correct option is D $12^{\circ} C$
$Q = m s △ t$
$△ t = \frac{Q}{m s} = \frac{7200}{5 \times 120} = 12^{\circ}$

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Specific heat capacity of lead is 120 J kg−1 K−1. When 7200J of heat is supplied to 5kg of lead, the rise in temperature is

The correct option is D 12∘CQ=ms△t△t=Qms=72005×120=12∘

Specific heat capacity of lead is $120 J k g^{- 1} K^{- 1}$ . When $7200 J$ of heat is supplied to $5 k g$ of lead, the rise in temperature is

The correct option is D $12^{\circ} C$
$Q = m s △ t$
$△ t = \frac{Q}{m s} = \frac{7200}{5 \times 120} = 12^{\circ}$