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Atoms and Molecules

Specific heat...

Question

Specific heat of a metal is 0.1 cal/g and its equivalent weight is 31.8 its exact atomic weight is

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Solution

atomic weightspecific heat = 6.4 (approx.)
atm weight = 6.4/0.1 = 64
valency = 64/31.8 =2.012
exact weight = eq. weight valency
= 2.012*31.8
= 63.981

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