Specific heat of a solid element is $0.1 c a l / g^{o} C$ and its equivalent weight is $31.8$ . Its exact atomic weight is :

31.8

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63.6

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318

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95.4

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Solution

The correct option is C 63.6
Atomic weight $= \frac{6.4}{0.1} = 64$
$n_{f} = \frac{A W}{E W} = \frac{64}{31.8} = 2$
Atomic weight $= n_{f} \times E W = 2 \times 31.8 = 63.6$

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