Speed of a particle moving in a circle varies with time as, v=2t . Then
A
angle between velocity vector and acceleration vector is increasing with time
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B
at is constant while ar is increasing with time.
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C
both A and B are correct
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D
both A and B are wrong
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Solution
The correct option is C both A and B are correct at=dvdt. Where at is tangential acceleration, v is speed.
ar=v2gr where ar is radial acceleration, and v is speed.
Herr at=2 which is constant, and ar is increasing as v is increasing with time so both options are correct because as arincreases then net acceleration vector also bends towards ar so angle between velocity and acceleration vector increases.