1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Physics
Finding Average Velocity
Speed of a pa...
Question
Speed of a particle moving on a circular path of radius 2m is varying with time as v=(2t^)m/s. Net acceleration of the particle at t=2s is 8√n m/s^2. The value of n is
Open in App
Solution
Suggest Corrections
0
Similar questions
Q.
The speed of a particle moving in a circle of radius r = 2 m varies with time t as
v
=
t
2
where t is in second and v in m/s. The net acceleration at t =2 s is
Q.
The speed of a particle moving in a circle of radius
r
=
2
m
varies with time
t
as
v
=
t
2
where
t
is in second and
v
in m/s. Find the radial, tangential and net acceleration at
t
=
2
s
.
Q.
A particle is moving on a circular path of radius
3
c
m
with a time varying speed of
v
=
3
t
c
m
/
s
, where
t
is in seconds. The magnitude of tangential acceleration and the total acceleration of the particle at
t
=
1
s
is
Q.
A particle is moving on a circular path of radius
1
m
with
2
m
/
s
. If speed starts increasing at a rate of
2
m
/
s
2
, then the acceleration of the particle is
Q.
Velocity in
m
/
s
of a particle moving along
x
−
axis varies with time as
v
=
(
10
+
5
t
−
t
2
)
. At time
t
=
0
,
x
=
0.
Acceleration of particle at
t
=
2
s
is
x
m
/
s
2
, then value of
x
is
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Speed and Velocity
PHYSICS
Watch in App
Explore more
Finding Average Velocity
Standard XII Physics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app