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Question

Speed of sound in air is 320 m/s. A pipe closed at one ends has a length of 1 m and there is another pipe open at both ends having a length of 1.6 m. Neglecting and corrections, both the air columns in the pipes can resonate for sound of frequency :

A
80 Hz
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B
240 Hz
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C
320 Hz
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D
400 Hz
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Solution

The correct option is D 400 Hz
The closed organ pipe can vibrate at frequency of f=vλ

λ14=1 f1=3204=80 Hz

3λ24=1 f2=3×3204=240 Hz

5λ34=1 f3=5×3204=400 Hz

The open organ pipe can vibrate at frequency of f=vλ

λ12=1.6 f1=3203.2=100 Hz

λ2=1.6 f2=×3201.6=200 Hz

3λ32=1.6 f3=3×3203.2×2=300 Hz

2λ2=1.6 f4=×3200.8=400 Hz

Hence both pipes can vibrate at 400 Hz frequency

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