Question

Speed of sound wave in a gas is $v_1$ and tins speed of molecules of the gas at the same temperature is $v_2$. Then :

• A. $v_1=v_2$
• B. $v_1<v_2$
• C. $v_1>v_2$
• D. $v_1\le v_2$

Answer 1

The correct option is B $v_1<v_2$

$\text{Explanation:-}$

We know that

Speed of sound in the gas, $v_1=\sqrt{\frac{rRt}{M}}$

RMS speed of gas molecule, $v_2=\sqrt{\frac{3Rt}{M}}$

Here

$r<T$

$\therefore v_1<v_2$

$\text{Hence the correct option is B}$