Speed of sound wave is v. If a reflector moves towards a stationary source emitting waves of frequency f with speed u, the wavelength of reflected waves will be
A
v−uv+uf
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B
v+uvf
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C
v+uv−uf
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D
v−uvf
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Solution
The correct option is Cv+uv−uf Apparent frequency for reflector (which will act here as an observer) would be f1=(v+uv)f Where f is the actual frequency of source. The reflector will now behave as a source. The apparent frequency will now become f2=(vv−u)f1
Substituting the value of f1 we get f2=(v+uv−u)f