Spheres of iron and lead having same mass are completely immersed in water. Density of lead is more than that of iron. Apparent loss of weight is $W_{1}$ for iron sphere and $W_{2}$ for lead sphere. Then $\frac{W_{1}}{W_{2}}$ is

= 1

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Between

0

and

1

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= 0

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> 1

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Solution

The correct option is C $> 1$
According to Archimedes' principle, force of buoyancy is given by $F_{B} = V ρ g; F_{B} \propto V$ where $V$ = Volume of immersed object $ρ$ = density of fluid $g$ = acceleration due to gravityApparent loss of weight is the weight of the fluid displaced by body. Lead is denser than iron, so equal mass of lead will have lesser volume than iron . So volume of water displaced and hence buoyant force exerted by the fluid (resulting in apparent loss of weight) will be more in iron $W_{1}$ than lead $W_{2}$ .

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Spheres of iron and lead having same mass are completely immersed in water. Density of lead is more than that of iron. Apparent loss of weight is W1 for iron sphere and W2 for lead sphere. Then W1W2 is

Spheres of iron and lead having same mass are completely immersed in water. Density of lead is more than that of iron. Apparent loss of weight is $W_{1}$ for iron sphere and $W_{2}$ for lead sphere. Then $\frac{W_{1}}{W_{2}}$ is