Question

Spin only magnetic moment of an octahedral complex of $F{e}^{2+}$ in the presence of a strong field ligand in $BM$ is

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• A. $0$
• B. $2.82$
• C. $4.89$
• D. $3.46$

Answer 1

The correct option is A $0$

The electronic configuration of $F{e}^{2+}\text{is}3d^{6}4s^0.$ In presence of strong field ligand $\left(L\right)$ resulting in the formation of inner orbital octahedral complex the electronic configuration of $F{e}^{2+}$ would be
$[Fe{L}_6{]}^{4-}:t_2^6{e}_g^0$
No unpaired electron, so,
Magnetic moment, $\mu =0$