Question

‘Spin only’ magnetic moment of Ni in $\left[Ni\right(dmg{)}_2]$ is same as that found in:

• A. Ni in $\left[NiC{l}_2\right(PP{h}_3{)}_2]$
• B. Mn in $[Mn{O}_4{]}^{-}$
• C. Co in $[CoB{r}_4{]}^{2-}$
• D. Pt in $\left[Pt\right(H_{2}O{)}_{2}B{r}_2]$

Answer 1

Answer: (B), (D)

The correct options are
B Mn in $[Mn{O}_4{]}^{-}$
D Pt in $\left[Pt\right(H_{2}O{)}_{2}B{r}_2]$

Ni in the complex $\left[Ni\right(dmg{)}_2]$ has no unpaired electrons,


Therefore the spin only magnetic moment would be zero.

Only $M{n}^{7+}$ and $P{t}^{2+}$ have no unpaired electrons