Spin only magnetic moment of the compound Hg[Co(SCN)4] is
√3
√15
√24
√8
Hg[Co(SCN)4], Co(Z = 27) ⇒3d7 4s2, Co2+=3d7
Unpaired electrons, n = 3
Magnetic moment =√n(n+2)=√3(3+2)=√15 BM