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Question

Spin only magnetic moment of the compound Hg[Co(SCN)4] is


A

3

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B

15

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C

24

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D

8

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Solution

The correct option is B

15


Hg[Co(SCN)4], Co(Z = 27) 3d7 4s2, Co2+=3d7

Unpaired electrons, n = 3

Magnetic moment =n(n+2)=3(3+2)=15 BM


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