Question

Split $207$ into three parts such that are in A.P. and the product of the two smaller parts is $4623$

Answer 1

let the no.s be $(a-d),a(a+d)$

$\Rightarrow$$a+a-d+a+d=207$

$\Rightarrow$$3a=207$

$\Rightarrow$$a=69$

let the two smaller parts be $a,(a+d)$

so

$\Rightarrow$$a(a+d)=4623$

$\Rightarrow$$69(69+d)=4623$

$\Rightarrow$$69+d=67$

$\Rightarrow$$d=-2$

no.s are $67,69,71$