-142- 21 - 28-153-17 - 4-44-2

The correct option is A √(14^2×21÷28+153+17×4 44) = (?)^2 √(14^2×21/28+153+68 44) = (?)^2 √(147+153+68 44) = (?)^2 √(240 44) = (?)^2 √(324) = (?)^2 18 = (?)^2 ...

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Byju's Answer

Standard XII

Mathematics

Pre-Image

√142× 21 ÷ 28...

Question

$\sqrt{14^{2} \times 21 \div 28 + 153 + 17 \times 4 - 44} = (?)^{2}$

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Solution

The correct option is A

$\sqrt{14^{2} \times 21 \div 28 + 153 + 17 \times 4 - 44} = (?)^{2}$
$\sqrt{\frac{14^{2} \times 21}{28} + 153 + 68 - 44} = (?)^{2}$
$\sqrt{147 + 153 + 68 - 44} = (?)^{2}$
$\sqrt{240 - 44} = (?)^{2}$
$\sqrt{324} = (?)^{2}$
$18 = (?)^{2}$
$(? = \sqrt{9 \times 2})^{2}$
$? = 3 \sqrt{2}$

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√142×21÷28+153+17×4−44=(?)2

The correct option is A √142×21÷28+153+17×4−44=(?)2 √142×2128+153+68−44=(?)2 √147+153+68−44=(?)2 √240−44=(?)2 √324=(?)2 18=(?)2 (?=√9×2)2 ?=3√2

$\sqrt{14^{2} \times 21 \div 28 + 153 + 17 \times 4 - 44} = (?)^{2}$