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Degree of a Polynomial

√2 is a polyn...

Question

$\sqrt{2}$ is a polynomial of degree

2

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0

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1

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\frac{1}{2}

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Solution

The correct option is A $0$
We can write it as $\sqrt{2} = \sqrt{2} \times x^{0}$
Thus, degree is 0.

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Similar questions

✓2 is a polynomial of degree (a)2 (b)0 (c)1 (d)½

$\sqrt{3}$ is a polynomial of degree
(a) $\frac{1}{2}$
(b) $2$
(c) $1$
(d) $0$

P (2) = - 1

P^{'} (2) = 0

P^{''} (2) = 2

P^{'''} (2) = - 12

P^{i v} (2) = 24

P^{''} (1)

f (x)

2

f (0) = 1,

a n d f^{''} (0) = 6,

\int_{- 1}^{2} f (x) d x

P (x)

4

P (2) = - 1, P^{'} (2) = 0, P^{''} (2) = 2, P^{'''} (2) = - 12, P^{''''} (2) = 24

P^{^{''}} (1) =

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