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Byju's Answer
Standard XII
Mathematics
Sum of n Terms
√ 2+√ 2+√ 2+2...
Question
√
2
+
√
2
+
√
2
+
2
cos
8
θ
=
2
cos
θ
Open in App
Solution
√
2
+
√
2
+
√
2
+
2
cos
8
θ
⇒
√
2
+
√
2
+
√
2
×
2
cos
2
4
θ
⇒
√
2
+
√
2
+
2
cos
4
θ
⇒
√
2
+
2
cos
2
θ
⇒
2
cos
θ
θ
=
n
π
for all values of
n
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0
Similar questions
Q.
Prove that
√
2
+
√
2
+
√
2
+
2
cos
8
θ
=
2
cos
θ
Q.
show that
√
2
+
√
2
+
√
2
+
2
cos
8
θ
=
2
cos
θ
,
0
<
θ
<
π
8
Q.
√
2
+
√
2
+
√
2
+
2
cos
8
θ
=
a
cos
θ
,
0
<
θ
<
π
/
16
.Find
a
Q.
Prove that
√
2
+
√
2
+
√
2
+
2
c
o
s
8
θ
=
2
c
o
s
θ
.
Or
Prove that
(
1
+
c
o
s
π
8
)
(
1
+
c
o
s
3
π
8
)
(
1
+
c
o
s
5
π
8
)
(
1
+
c
o
s
7
π
8
)
=
1
8
Q.
Solve :-
√
2
+
√
2
+
2
cos
4
θ
=
2
cos
θ
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