The correct option is A 10√(2601)+√(169)= 8^12 ? ⇒ 51+13 = 8^12 ?⇒ 64 = 8^12 ?⇒ 8^2 = 8 ^12 ? ⇒ ?= 10 ...

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Applications of Dot Product

√2601+√169=81...

Question

$\sqrt{2601} + \sqrt{169} = 8^{12 - ?}$

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Solution

The correct option is A 10
$\sqrt{2601} + \sqrt{169} = 8^{12 - ?} \Rightarrow 51 + 13 = 8^{12 - ?} \Rightarrow 64 = 8^{12 - ?} \Rightarrow 8^{2} = 8^{12 - ?} \Rightarrow ? = 10$

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