729 = 9 x 9x 9 ∴ √(729)= √(9× 9× 9) nbsp; = 9 nbsp; 3^3 = 3× 3× 3 = 27 So, √(729) +3^3 = 9+27 = 36 =6^ ...

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Cubes Relation with Cube Numbers

√729 + 33 =

Question

$\sqrt[3]{729} + (3)^{3}$ = ________

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Solution

729 = 9 x 9x 9
$∴$ $\sqrt[3]{729} = \sqrt[3]{9 \times 9 \times 9} = 9$

$3^{3} = 3 \times 3 \times 3 = 27$

So, $\sqrt[3]{729} + 3^{3} = 9 + 27 = 36 = 6^{2}$

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3^{- 2} \times 81^{\frac{3}{4}} \div 729^{- \frac{1}{3}}

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\sqrt[3]{64} \times \sqrt[3]{729} = \sqrt[3]{64 \times 729}

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