wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

3cosθ+sinθ=1;2π<θ<2π

Open in App
Solution

We have,
3cosθ+sinθ=1
Since, sinθ=1cos2θ
Therefore,
(13cosθ)2=1cos2θ
1+3cos2θ23cosθ=1cos2θ
4cos2θ23cosθ=0
4cosθ=23
cosθ=234=32
θ=cos132=π6 or 2ππ6=11π6
But
θ=11π6 is only correct by putting in the equation.
Hence, this is the answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon