The correct option is C 1/2 Prime factorization 16 and 128, 16 = 2^ 4 128 = 2^ 7 16 / 128 = 1 / 2^ 3 √( ...

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Intersection

√-16/128 is e...

Question

$\sqrt[3]{\frac{- 16}{128}}$ is equal to

\frac{4}{12}

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\frac{1}{2}

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- \frac{1}{2}

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none of these

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Solution

The correct option is C $- \frac{1}{2}$
$P r i m e f a c t o r i z a t i o n 16 a n d 128, 16 = 2^{4} 128 = 2^{7} \frac{- 16}{128} = \frac{- 1}{2^{3}} \sqrt[3]{\frac{- 16}{128}} = \frac{- 1}{2}$

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