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Question

3+i=(a+ib)(c+id),thentan1ba+tan1dc

has the value


A

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B

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C

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D

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Solution

The correct option is B


3+i=(a+ib)(c+id)

acbd=3 and ad+bc=1

Now tan1(ba)+tan1(dc)

= tan1(ab+dc1ba.dc)= tan1(bc+adacbd)= tan1(13)

=nπ+π6, nϵI


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