$\sqrt{3} sin x + cos x$ is maximum, when x is

30^{o}

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90^{o}

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60^{o}

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45^{o}

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Solution

The correct option is C $60^{o}$
$\sqrt{3} sin x + cos x = 2 (sin x \frac{\sqrt{3}}{2} + \frac{1}{2} cos x)$
$= 2 sin (x + \frac{π}{6})$
Maximum occurs at $x = \frac{π}{3} = 60^{o}$
Option $C$

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