$\sqrt{3} \times \sqrt{12} + 4 \div \sqrt{2} - \sqrt{8} =$

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Solution

$\sqrt{3} \times \sqrt{12} + 4 \div \sqrt{2} - \sqrt{8}$
According to PEMDAS rule, here first we will solve multiplication then division then addition and then subtraction.
$\sqrt{3 \times 12} + 4 \div \sqrt{2} - \sqrt{8} = 6 + 2 \sqrt{2} - 2 \sqrt{2} = 6$

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√3×√12+4÷√2−√8=

√3×√12+4÷√2−√8 According to PEMDAS rule, here first we will solve multiplication then division then addition and then subtraction. √3×12+4÷√2−√8=6+2√2−2√2=6

$\sqrt{3} \times \sqrt{12} + 4 \div \sqrt{2} - \sqrt{8} =$

$\sqrt{3} \times \sqrt{12} + 4 \div \sqrt{2} - \sqrt{8}$
According to PEMDAS rule, here first we will solve multiplication then division then addition and then subtraction.
$\sqrt{3 \times 12} + 4 \div \sqrt{2} - \sqrt{8} = 6 + 2 \sqrt{2} - 2 \sqrt{2} = 6$