The correct option is E None of theseHere, √(25 × 14 6 × 7 + (4)^?) = 18 ⇒√(350 42 + (4)^?) = 18 ⇒√(350 42 + (4)^?) = 18 Taking squares on both sides, we ...

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Standard VIII

Mathematics

Adding Consecutive Odd Numbers

√52× 14-6 × 7...

Question

$\sqrt{5^{2} \times 14 - 6 \times 7 + (4)^{?}} = 18$

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Solution

The correct option is E None of these
$H e r e, \sqrt{25 \times 14 - 6 \times 7 + (4)^{?}} = 18 \Rightarrow \sqrt{350 - 42 + (4)^{?}} = 18 \Rightarrow \sqrt{350 - 42 + (4)^{?}} = 18$
Taking squares on both sides, we get
$350 - 42 + (4)^{?} = 324 \Rightarrow (4)^{?} = 16 \Rightarrow (4)^{?} = (4)^{2} \Rightarrow ? = 2$

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Q. Solve:

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\begin{matrix} (2) & 4 & 14 (6) & 7 & 43 (. . . .) & 5 & 18 \end{matrix}

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A bag contains sugar that weighs $6 \frac{7}{9}$ kg and rice that weighs $7 \frac{5}{6}$ .Find the total weight of the bag ?

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√52×14−6×7+(4)?=18

The correct option is E None of theseHere,√25×14−6×7+(4)?=18⇒√350−42+(4)?=18⇒√350−42+(4)?=18 Taking squares on both sides, we get 350−42+(4)?=324⇒(4)?=16⇒(4)?=(4)2⇒?=2

$\sqrt{5^{2} \times 14 - 6 \times 7 + (4)^{?}} = 18$