$\sqrt[5]{4}$ into a surd of order 10 is

\sqrt[10]{16}

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\sqrt[10]{8}

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\sqrt[10]{64}

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\sqrt[10]{4}

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Solution

The correct option is A $\sqrt[10]{16}$
$\sqrt[5]{4} = \sqrt[5 \times 2]{4^{2}} = \sqrt[10]{4 \times 4} = \sqrt[10]{16}$

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