$(\sqrt{9})^{3} \times (\sqrt{81})^{5} \div (27)^{2} = (3)^{(?)}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is E None of these
Here, applying the rules of surds and indices, we get
$(9)^{\frac{3}{2}} \times (9)^{\frac{5}{2}} \div (27)^{2} = (3)^{?} \Rightarrow (3)^{2 \times \frac{3}{2}} \times (3)^{2 \times \frac{5}{2}} \div (3^{3})^{\times 2} = (3)^{?} \Rightarrow 3^{3 + 5 - 6} = (3)^{?} \Rightarrow ? = 2$

Suggest Corrections

Similar questions

Q. If, 1111=5
2222=24
3333=93
4444=272
5555=?

Q. Find the value of m, from the following cumulative frequency distribution of more than type .

$\begin{matrix} C l a s s & F r e q u e n c y & M o r e t h a n I n t e r v a l & c u m u l a t i v e f r e q u e n c y 0 - 3 & 10 & m 3 - 6 & 15 & 93 - 10 = 83 6 - 9 & 18 & 83 - 15 = 68 9 - 12 & 22 & 68 - 18 = 50 12 - 15 & 16 & 50 - 22 = 28 15 - 18 & 12 & 28 - 16 = 12 \end{matrix}$

Simplify $\frac{{(27)}^{\frac{2}{3}}}{{(9)}^{\frac{1}{2}} {(3)}^{\frac{3}{2}}}$

Q. Prove

(27)^{2 / 3} = 9

Q. What is

27^{2 / 3}

Join BYJU'S Learning Program

(√9)3×(√81)5÷(27)2=(3)(?)

The correct option is E None of theseHere, applying the rules of surds and indices, we get (9)32×(9)52÷(27)2=(3)?⇒(3)2×32×(3)2×52÷(33)×2=(3)?⇒33+5−6=(3)?⇒?=2

$(\sqrt{9})^{3} \times (\sqrt{81})^{5} \div (27)^{2} = (3)^{(?)}$