$\sqrt{\frac{37 - \sqrt{144}}{37 + \sqrt{144}}}$

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Solution

$\sqrt{\frac{37 - \sqrt{144}}{37 + \sqrt{144}}} \sqrt{\frac{37 - 12}{37 + 12}} \sqrt{\frac{25}{49}} = \frac{5}{7}$

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Similar questions

Q. Given

5 (x + 4) - 8 (4 - x) = 25 - 3 (7 - x) + 144

, then the value of x is

Subtract:
(i) 28 from − 42
(ii) − 36 from 42
(iii) − 37 from − 53
(iv) − 66 from − 34
(v) 318 from 0
(vi) − 153 from − 240
(vii) − 64 from 0
(viii) − 56 from 144

Q. Which of the following numbers are even and which are odd?
(i) 32
(ii) 37
(iii) 50
(iv) 58
(v) 69
(vi) 144
(vii) 321
(viii) 253

The statement 'Product of 7 and 13z is equal to 144z' can be repseneted as :

Q. To divide 144 by 8, we split 144 as ___ and 64.

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√37−√14437+√144

√37−√14437+√144√37−1237+12√2549=57

$\sqrt{\frac{37 - \sqrt{144}}{37 + \sqrt{144}}}$

$\sqrt{\frac{37 - \sqrt{144}}{37 + \sqrt{144}}} \sqrt{\frac{37 - 12}{37 + 12}} \sqrt{\frac{25}{49}} = \frac{5}{7}$