- s-cs-a ss-b s-cs-a ss-b - s-as-b ss-c s-as-b ss-c is equal to -

Given, √( (s c)(s a) s(s b) #160; (s c)(s a) s(s b) #160; #160; ) √( (s a)(s b) s(s c) #160; (s a)(s b) s(s c) #160; #160; ) = ...

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Integers

√ s-cs-a ss-b...

Question

$\sqrt{\frac{\frac{(s - c) (s - a)}{s (s - b)}}{\frac{(s - c) (s - a)}{s (s - b)}}} - \sqrt{\frac{\frac{(s - a) (s - b)}{s (s - c)}}{\frac{(s - a) (s - b)}{s (s - c)}}}$ is equal to ____.

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The area of a triangle, with sides $a, b, c$ and semi-perimeter $s$ , is:

△ A B C, (s - a) (s - b) = s (s - c),

C

A B C, (s - a) (s - b) = s (s - c)

C

Δ A B C

a, b, c,

{tan}^{- 1} (\frac{b}{c + a}) + {tan}^{- 1} (\frac{c}{a + b}) = \frac{π}{4}

a + b + c = 2 s

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